(2x-5)(2x-15)=4x^2+5x

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Solution for (2x-5)(2x-15)=4x^2+5x equation: 



(2x-5)(2x-15)=4x^2+5x

We move all terms to the left:

(2x-5)(2x-15)-(4x^2+5x)=0

We get rid of parentheses

-4x^2+(2x-5)(2x-15)-5x=0

We multiply parentheses ..

-4x^2+(+4x^2-30x-10x+75)-5x=0

We get rid of parentheses

-4x^2+4x^2-30x-10x-5x+75=0

We add all the numbers together, and all the variables

-45x+75=0

We move all terms containing x to the left, all other terms to the right

-45x=-75

x=-75/-45

x=1+2/3

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